Steve Donahue / SeeSpotRun Photo
A 4-year-old Scottish deer dog named Claire has won Best in Show at the National Dog Show, for the second time in two years. The black and taupe long-legged hound hounds her nose at the camera and smiles widely before scurrying to pick up her tape with her handler, Angela Lloyd.
Claire beat out hundreds of other dogs at the annual show, which is hosted by the Kennel Club of Philadelphia. The show took place over the weekend but the winner was announced during an NBC broadcast on Thanksgiving Day.
This is the first time in 20 years that a dog has won twice in a row. Lloyd said Claire has been “more confident” this year.
The Scottish deerhound is one of the tallest dog breeds—large males can stand 32 inches at the shoulder and weigh more than 100 pounds, according to the American Kennel Club. The breed has superior hunting ability and was bred to track giant wild red deer. The AKC suggests that you need to stand farther away when staring at a Scottish Deer dog “to fully appreciate the greatness of this ancient beast.”
Other finalists on the show include the English Winter Bulldog, MMT Lakeland Terrier, Sasha the Pyrenean Shepherd, Chester the Avenbincher, Jade the German Shorthaired Pointer and Mo’Ne the Kuvasz, a working dog.
There were 196 breeds and varieties of dog that were recognized by the AKC at this year’s show. This includes its newest recognized breed, the Biewer Terrier, which debuted on the show and was described by NBC as “a stylish, sporty terrier whose only purpose in life is to be loved and loved.” A rumor, a 19-month-old female Biewer Terrier, featured a bright blue bow.
More than 2,000 dogs normally compete in this event, but last year the number was reduced by about 70% due to COVID-19 restrictions. Last year’s competition was held without spectators, but this year it was allowed to fully immunize spectators.